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Question

Mathematics Question on Trigonometric Functions

The value of cos248sin212\cos^2 \, 48^{\circ} - \sin^2 12^{\circ} is

A

5+18\frac{\sqrt{5} + 1}{8}

B

518\frac{\sqrt{5} - 1}{8}

C

5+15\frac{\sqrt{5} + 1}{5}

D

5+122\frac{\sqrt{5} + 1}{ 2\sqrt{2}}

Answer

5+18\frac{\sqrt{5} + 1}{8}

Explanation

Solution

Answer (a) 5+18\frac{\sqrt{5} + 1}{8}