Question

The value of cos 1200° + tan 1485° is

• A. $\frac{1}{2}$
• B. $\frac{3}{2}$
• C. $-\frac{3}{2}$
• D. $-\frac{1}{2}$

Answer 1

Answer: (A)

$\frac{1}{2}$

Answer 2

The correct answer is () :