Question

The value of c of the mean value theorem,

If f(x) = x(x – 1) (x – 2) ; a = 0, b = 1/2 is :

• A. 1
• B. 1 + $\sqrt{(21)}/6$
• C. 1 – $\sqrt{(21)}/6$
• D. None

Answer 1

Answer: (C)

1 – $\sqrt{(21)}/6$

Answer 2

f ¢(3) = $\frac{f(b) - f(a)}{b - a}$, c = 1 – $\frac{\sqrt{21}}{6}$

clearly option A, B not in (0, 1)