QuestionReportMathematics Question on MatricesThe value of ∣√3212√3212∣\begin {vmatrix} \frac{√3}{2}&\frac{1}{2} \\\\\frac{√3}{2} &\frac{1}{2}\end {vmatrix}2√32√32121A0B1C32\frac{\sqrt{3}}{2}23D12\frac{1}{2}21Answer0ExplanationSolutionThe correct option is (A):0