Question
Question: The value of an odd order skew-symmetric determinant is A.Perfect square B.Negative C.\[\pm 1\...
The value of an odd order skew-symmetric determinant is
A.Perfect square
B.Negative
C.±1
D.0
Solution
Hint: Assume an odd skew-symmetric matrix A. We know that the determinant value of skew-symmetric matrix A and the determinant value of transpose of skew-symmetric matrix A are equal to each other. That is, det(A)=det(AT) . Also, the transpose matrix A is equal to the negative of the matrix A. If two matrices are equal then their determinant values are also equal. So, det(AT)=det(−A) . We know the formula that, det(−A)=(−1)ndet(A) where n is the order of the matrix A. Using this formula for det(−A) and take n as odd. If n is odd then (−1)n is equal to -1. Now, solve it further.
Complete step-by-step answer:
According to the question, it is given that we have an odd order skew-symmetric determinant.
An odd order means an odd number of rows and columns. It means we have an odd number of rows and columns in an odd skew-symmetric matrix.
Let us assume an odd skew symmetric square matrix having order n, where n is odd.
We know the property that,
det(A)=det(AT) ………………………..(1)
where, AT is the transpose of matrix A.
We also know that for a skew-symmetric matrix, AT=−A .
If two matrices are equal then its determinant values are also equal, so det(AT)=det(−A) …………..(2)
We know the formula that, det(−A)=(−1)ndet(A) where n is the order of the matrix A.
From equation (2) and the above equation, we get
det(AT)=(−1)ndet(A) …………………(3)
Here, n is the order of the matrix A and n is odd.
(−1)n=−1 ………………….(4)
From equation (3) and equation (4), we have
det(AT)=(−1)ndet(A)
⇒det(AT)=−det(A) ……………..(5)
From equation (1) and equation (5), we get
det(A)=det(AT)