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Question

Question: The value of \(\alpha,\beta\) is....

The value of α,β\alpha,\beta is.

A

ax2+bx+c=0ax^{2} + bx + c = 0

B

α+β,\alpha + \beta,

C

α2+β2,\alpha^{2} + \beta^{2},

D

None of these

Answer

α+β,\alpha + \beta,

Explanation

Solution

Let 5,4,1±532- 5,4,\frac{- 1 \pm 5\sqrt{-}3}{2}

5,4,1±5325,4,\frac{- 1 \pm 5\sqrt{-}3}{2} (on simplification)

5,4,1±532- 5, - 4,\frac{1 \pm 5\sqrt{-}3}{2}

But the value of the given expression cannot be negative or less than 2, therefore x33x2+x+5=0x^{3} - 3x^{2} + x + 5 = 0 is required answer.