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Question: The value of acceleration due to gravity (g) at a height h above the surface of earth is given by \...

The value of acceleration due to gravity (g) at a height h above the surface of earth is given by g=gR2(R+h)2g ^ { \prime } = \frac { g R ^ { 2 } } { ( R + h ) ^ { 2 } } If h<<Rh < < R then

A

g=g(1hR)g ^ { \prime } = g \left( 1 - \frac { h } { R } \right)

B

g=g(12hR)g ^ { \prime } = g \left( 1 - \frac { 2 h } { R } \right)

C

g=g(1+hR)g ^ { \prime } = g \left( 1 + \frac { h } { R } \right)

D

g=g(1+2hR)g ^ { \prime } = g \left( 1 + \frac { 2 h } { R } \right)

Answer

g=g(12hR)g ^ { \prime } = g \left( 1 - \frac { 2 h } { R } \right)

Explanation

Solution

g=g(RR+h)2g ^ { \prime } = g \left( \frac { R } { R + h } \right) ^ { 2 }=(1+hR)2\left( 1 + \frac { h } { R } \right) ^ { - 2 }

g=g(12hR)g ^ { \prime } = g \left( 1 - \frac { 2 h } { R } \right) ( if hR\frac { h } { R }.)