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Physics Question on Gravitation

The value of acceleration due to gravity ′g′'g', at earth's surface is 10 m/s2.10\, m / s ^{2} . Its value at the centre of the earth which is assumed to be sphere of radius ′R′' R' and uniform mass density, is

A

2.5 R m/s22.5\, R\, m / s ^{2}

B

5 R m/s25\, R\, m / s ^{2}

C

10 R m/s210\, R\, m / s ^{2}

D

0

Answer

0

Explanation

Solution

Acceleration due to gravity at a depth h from the earth�s surface g′=g(1−hR)=g(1−RR)=g(1−1)=0.\quad\quad g'=g\left(1-\frac{h}{R}\right)=g\left(1-\frac{R}{R}\right)=g\left(1-1\right)=0.