Question

The value of $A = \frac{\pi}{3},B = \frac{\pi}{6}$ satisfying the given equation

$2 - 2\cos^{2}\theta + \sqrt{3}\cos\theta + 1 = 0$ = 2, is .

• A. $\Rightarrow$
• B. $2\cos^{2}\theta - \sqrt{3}\cos\theta - 3 = 0$
• C. $\Rightarrow$
• D. $\cos\theta = \frac{\sqrt{3} \pm \sqrt{3 + 24}}{4} = \frac{\sqrt{3}(1 \pm 3)}{4} = \sqrt{3}\left( - \frac{1}{2} \right)$

Answer 1

Answer: (A)

$\Rightarrow$

Answer 2

$x = bc$.