The value of a(≠0) for which the equation (\frac{1}{2}(x-2)^... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

The value of a(≠0) for which the equation $\frac{1}{2}(x-2)^2+1=\sin(\frac{a}{x})$ holds is/are

A

$(4n+1)\pi,n\isin \Z$

B

$2(n-1)\pi,n\isin \Z$

C

$n\pi,n\isin \N$

D

$\frac{n\pi}{2},\isin \N$

E

1

Answer

$(4n+1)\pi,n\isin \Z$

Explanation

Solution

The correct option is (A): $(4n+1)\pi,n\isin \Z$