Question
Mathematics Question on Combinations
The value of −15C1+2.15C2−3.15C3+… −15.15C15+14C1+14C3+14C5+….+14C11 is
A
216−1
B
213−14
C
214
D
213−13
Answer
213−14
Explanation
Solution
(−15C1+215C2−3.15C3+…−15.15C15) +(14C1+14C3+….+14C11) =r=1∑15(−1)r⋅r15Cr+(14C1+14C3+…+14C11+14C13)−14C3 =r=1∑15(−1)r15⋅14Cr−1+213−14 =15(−14C0+14C1…−14C14)+213−14 =213−14