Question
Mathematics Question on complex numbers
The value of (1+ω−ω2)7 is
A
128ω2
B
−128ω2
C
128ω
D
−128ω
Answer
−128ω2
Explanation
Solution
(1+ω−ω2)7=(−ω2−ω2)7=(−2ω2)7 =−128(ω4)3ω2=−128ω2
The value of (1+ω−ω2)7 is
128ω2
−128ω2
128ω
−128ω
−128ω2
(1+ω−ω2)7=(−ω2−ω2)7=(−2ω2)7 =−128(ω4)3ω2=−128ω2