Question

The value of $1+\bigg(1+\frac{1}{3}\bigg)\frac{1}{4}+\bigg(1+\frac{1}{3}+\frac{1}{9}\bigg)\frac{1}{16}+\bigg(1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\bigg)\frac{1}{64}+....$,is

• A. $\frac{15}{13}$
• B. $\frac{27}{12}$
• C. $\frac{16}{11}$
• D. $\frac{15}{8}$

Answer 1

Answer: (C)

$\frac{16}{11}$

Answer 2

The correct option is (C): $\frac{16}{11}$.