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Question

Mathematics Question on Sum of First n Terms of an AP

The value of 1.2.3 + 2.3.4 +3.4.5 + ... + n terms is

A

n(n+1)(n+2)(n+3)12\frac{n(n + 1)(n + 2)(n + 3)}{12}

B

n(n+1)(n+2)(n+3)3\frac{n(n + 1)(n + 2)(n + 3)}{3}

C

n(n+1)(n+2)(n+3)4\frac{n(n + 1)(n + 2)(n + 3)}{4}

D

n(n+2)(n+3)(n+4)6\frac{n(n + 2)(n + 3)(n + 4)}{6}

Answer

n(n+1)(n+2)(n+3)4\frac{n(n + 1)(n + 2)(n + 3)}{4}

Explanation

Solution

Answer (c) n(n+1)(n+2)(n+3)4\frac{n(n + 1)(n + 2)(n + 3)}{4}