The value of (∫\_0^{\frac{\pi}{4}} \frac{dx}{1+tanx} ) | Mathematics | SolveeIt

The value of $∫_0^{\frac{\pi}{4}} \frac{dx}{1+tanx}$

$\frac{π}8 + In 2$

$\frac{π}4 + In 2$

$\frac{π}8 +\frac{1}2 In 2$

$\frac{π}8 +\frac{1}4 In 2$

Answer

$\frac{π}8 +\frac{1}4 In 2$

Explanation

The Correct answer is option is (D) : $\frac{π}8 +\frac{1}4 In 2$

Mathematics Question on Definite Integral