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Question

Engineering Mathematics Question on Double and triple integrals

The value of 0π20соsθr sinθ dr dθ∫_0^{\frac{π}{2}}∫_0^{соs \theta} r\text{ }sin\theta\text{ }dr\text{ }d\theta is

A

0

B

16\frac{1}{6}

C

43\frac{4}{3}

D

π\pi

Answer

16\frac{1}{6}

Explanation

Solution

The correct option is (B): 16\frac{1}{6}