The value of (∫\_0^{2\pi} sin^{2}nxdx), where (n∈I), is: | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

The value of $∫_0^{2\pi} sin^{2}nxdx$ , where $n∈I$ , is:

A

0

B

$\frac{\pi}{2}$

C

$\pi$

D

$2\pi$

Answer

$\pi$

Explanation

Solution

The correct option is (C): $\pi$