Question

The $v-t$ graph of a moving object is given in figure. The maximum acceleration is

• A. $1 \,cm / s ^{2}$
• B. $2\, cm / s ^{2}$
• C. $3\, cm / s ^{2}$
• D. $6\, cm / s ^{2}$

Answer 1

Answer: (D)

$6\, cm / s ^{2}$

Answer 2

The slope of the velocity-time ($v-t$) graph represents acceleration.

From the given figure, we have

Slope of the line AB = $\frac{20-0}{20}=1$

Slope of the line BC = 0

Slope of the line CD = $\frac{80-20}{40-30}=6$

Slope of the line DE = $\frac{80-0}{80-40}=2$

Slope of $v-t$ graph is maximum for line CD during the time interval $30\, s$ to $40\, s$.

Hence the maximum acceleration is $6cm/s^2$

Discover More from Chapter:Graphical Representation of Motion