Solveeit Logo

Question

Physics Question on applications of diode

The V-I characteristic of a diode is shown in the figure. The ratio of forward to reverse bias resistance is:V-I characteristic of a diode

A

10

B

10-6

C

106

D

100

Answer

10-6

Explanation

Solution

The forward I-V characteristic is when the diode is forward-biased, and the anodewith respect to the cathode is positive. On the other hand, the reverse I-V characteristics are observed when the cathode is positive with respect to the anode.

Formula Used:

Forward bias resistance Rf is given as - Rf=ΔVfΔIfR_f=\frac{ΔV_f}{ΔI_f}

  • where, ΔVfΔV_f is the difference between forward bias voltages,
  • ΔIfΔI_f is the difference between currents.

Reverse bias resistance RrR_r is given as - Rr=ΔVrΔIrR_r=\frac{ΔV_r}{ΔI_r}

  • where, ΔVrΔV_r is the difference between reverse bias voltages,
  • ΔIrΔI_r is the difference between currents.

Complete step-by-step answer:

The forward resistance offered by a diode in forward bias is very small. On the other hand, a diode offers very high reverse resistancewhen it is in reverse bias.

The formula for forward bias resistance RfR_f is given as Rf=ΔVfΔIfR_f=\frac{ΔV_f}{ΔI_f}→................(1)

  • where, ΔVfΔV_f denotes the difference between forward bias voltages.
  • ΔIfΔI_f is the difference between currents approximating particular voltages.

From the given diagram, the current ranges from 10 to 20 milli-Amperes. Therefore, ΔIf=2010ΔI_f=20−10

ΔIf=10mA⇒ΔI_f=10mA

ΔIf=10×103A⇒ΔI_f=10×10^{−3}A

and the voltage ranges from 0.7 to 0.8 V.

ΔVf=0.80.7⇒ΔV_f=0.8−0.7

ΔVf=0.1V⇒ΔV_f=0.1V

Substituting the values in equation (1)

Rf=ΔVfΔIfR_f=\frac{ΔV_f}{ΔI_f}

Rf=0.110×103Ω⇒R_f=\frac{0.1}{10×10^{−3}Ω}

Rf=10Ω⇒R_f=10Ω

The formula for reverse bias resistance RrR_r is given as:

Rr=ΔVrΔIrR_r=\frac{ΔV_r}{ΔI_r}→................(2)

  • where, ΔVrΔV_r is the difference between reverse bias voltages
  • ΔIrΔI_r is the difference between currents corresponding to particular voltages.

Also according to the diagram, the reverse bias current will be

Rr=ΔVrΔIrR_r=\frac{ΔV_r}{ΔI_r}

Rr=10106Ω⇒R_r=\frac{10}{10^{−6}}Ω

Rr=107Ω⇒R_r=10^7Ω

Then, the ratio of forward bias to reverse bias resistance can be written as:

Ratio=RfRrRatio=\frac{R_f}{R_r}

Ratio=10107Ω⇒Ratio=\frac{10}{10^7}Ω

Ratio=106Ω∴Ratio=10^{−6}Ω

Hence, option B is the correct answer.

Note: The formula for reverse bias resistance and forward bias resistance can be written with the help of Ohm’s Law. Ohm’s law is given by V = IR.

  • where V is the voltage,
  • I is the current
  • R is the resistance.

Thus, resistance can be written as R = VI

Independently in terms of forward and reverse bias resistance, this equation becomes Rr=ΔVrΔIrR_r=\frac{ΔV_r}{ΔI_r}

And Rr=ΔVrΔIrR_r=\frac{ΔV_r}{ΔI_r} respectively.