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Question: The useful energy available by burning \(1g\) coal is \(2kcal\) . The cost of producing \(1Wh\) ener...

The useful energy available by burning 1g1g coal is 2kcal2kcal . The cost of producing 1Wh1Wh energy is (1kg coal=21paise)1kg{\text{ }}coal = 21paise)?
(A) 9paise9 paise
(B) 18paise18 paise
(C) 4.5paise4.5 paise
(D) 36paise36 paise

Explanation

Solution

We first have to check for unit consistency, energy is given in kcalkcal as well as joulesjoules and kilowatt hourkilowatt{\text{ }}hour So we first convert Everything to joulesjoules. In the question we are given how much coal is needed for 2kcal2kcal now we convert the 2kcal2kcal to joulesjoules. Then convert 1Wh1Wh energy to joulesjoules then find out how much coal is needed for 2kcal2kcal. Using the weight of coal found we find the price using the amount of coal price from the question. Unit consistency is very important.

Complete step by step solution:
Firstly converting all the given units of energies to joules,
2kcal=8400joules2kcal = 8400 joules
1kWh=3.6×106joules1kWh = 3.6 \times {10^6} joules
From the question we know that 2kcal=8400joules2kcal = 8400joules requires 1gm1gm coal, so for 1kwh=3.6×106joules1kwh = 3.6 \times {10^6} joules require ,
3.6×1068400×1=30007gms=37kg\dfrac{{3.6 \times {{10}^6}}}{{8400}} \times 1 = \dfrac{{3000}}{7}gms = \dfrac{3}{7}kg
We also know from the question that 1kg1kg coal costs 21paise21 paise so 37kg\dfrac{3}{7}kg will cost,
37×21=9paise\dfrac{3}{7} \times 21 = 9 paise
Hence the cost of producing 1kwh=3.6×106joules1kwh = 3.6 \times {10^6} joules of useful energy is 9paise9paise.

The correct answer is option (A), 9paise9paise.

Additional information: Coal-fired plants produce electricity by burning coal in a boiler to produce steam. The steam produced, under tremendous pressure, flows into a turbine, which spins a generator to create electricity. The steam is then cooled, condensed back into the water, and returned to the boiler to start the process over.

Note: This is a problem that needs basic math knowledge, the only tricky part of the question is to convert all the units of energy to a single common unit and solve for the weight of coal, and finding the cost from the cost in the question given data. The amount of energy released by one kilogram of coal during combustion is 3×107joules3 \times {10^7} joules.