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Question

Question: The upper quartile for the following distribution | | | | | | | ...

The upper quartile for the following distribution

Size of items1234567
Frequency2458732

is given by the size of

A

(31+14)\left( \frac{31 + 1}{4} \right)th item

B

[2(31+14)]\left\lbrack 2\left( \frac{31 + 1}{4} \right) \right\rbrackth item

C

[3(31+14)]\left\lbrack 3\left( \frac{31 + 1}{4} \right) \right\rbrackth item

D

[4(31+14)]\left\lbrack 4\left( \frac{31 + 1}{4} \right) \right\rbrackth item

Answer

[3(31+14)]\left\lbrack 3\left( \frac{31 + 1}{4} \right) \right\rbrackth item

Explanation

Solution

Upper Quartile = Size of [3(n+1)4]th\left\lbrack 3\frac{(n + 1)}{4} \right\rbrack^{th}item

= Size of [3(31+14)]th\left\lbrack 3\left( \frac{31 + 1}{4} \right) \right\rbrack^{th}item, [Σf=31]\lbrack\because\Sigma f = 31\rbrack.