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Question: The upper end of a wire of radius 4 mm and length 100 cm is clamped and its other end is twisted thr...

The upper end of a wire of radius 4 mm and length 100 cm is clamped and its other end is twisted through an angle of 30o30^{o}. Then angle of shear is

A

12o12^{o}

B

0.12o0.12^{o}

C

1.2o1.2^{o}

D

0.012o0.012^{o}

Answer

0.12o0.12^{o}

Explanation

Solution

Lφ=rθL\varphi = r\theta ∴φ=rθL=4×10−3×30o1=0.12o\therefore\varphi = \frac{r\theta}{L} = \frac{4 \times 10^{- 3} \times 30^{o}}{1} = 0.12^{o}