Solveeit Logo

Question

Physics Question on Stress Strain Curve

The upper end of a wire of diameter 12mm12\,mm and length 1m1\,m is clamped and its other end is twisted through an angle of 3030^{\circ}. The angle of shear is

A

1818^\circ

B

0.180.18^\circ

C

3636^\circ

D

0.360.36^\circ

Answer

0.180.18^\circ

Explanation

Solution

The correct option is (B): 0.180.18^\circ
rθ=1ϕr \theta=1 \phi
ϕ=rθ1=6mm×301m\Rightarrow \phi=\frac{ r \theta}{1}=\frac{6 mm \times 30^{\circ}}{1 m }
=0.18=0.18^{\circ}