Question

The unpaired electron in $Ni(CO)_{4}$ is

• A. 1
• B. 2
• C. 3
• D. 0

Answer 1

Answer: (D)

0

Answer 2

In $N i(C O)_{4}$, there is no unpaired electron.
It is diamagnetic.
Oxidation state of $N i$ in $\left[N i(C O)_{4}\right]$
complex compound is zero.
$N i=3 d^{8} 4 s^{2}$
$s p^{3}$ hybridised orbitals of $Ni$
$\left[N i(C O)_{4}\right]$