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Question

Chemistry Question on Ionic Equilibrium In Solution

The units of ionic product of water (Kw)(K_w) are

A

mol−1L−1mol^{-1} L^{-1}

B

mol−2L−2mol^{-2} L^{-2}

C

mol−2L−1mol^{-2} L^{-1}

D

mol2L−2mol^{2} L^{-2}

Answer

mol2L−2mol^{2} L^{-2}

Explanation

Solution

Kw=[H+][OH−]K_{w}=[H^{+}] [OH^{-}] Units of Kw=(mol L−1)(mol L−1)K_{w}=(mol\,L^{-1}) (mol\,L^{-1}) =mol2 L−2=mol^{2}\,L^{-2}