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Question

Question: The unit vector perpendicular to the vectors \(6 \mathbf { i } + 2 \mathbf { j } + 3 \mathbf { k }\)...

The unit vector perpendicular to the vectors 6i+2j+3k6 \mathbf { i } + 2 \mathbf { j } + 3 \mathbf { k } and 3i6j2k3 \mathbf { i } - 6 \mathbf { j } - 2 \mathbf { k } is

A

2i3j+6k7\frac { 2 \mathbf { i } - 3 \mathbf { j } + 6 \mathbf { k } } { 7 }

B

2i3j6k7\frac { 2 \mathbf { i } - 3 \mathbf { j } - 6 \mathbf { k } } { 7 }

C

2i+3j6k7\frac { 2 \mathbf { i } + 3 \mathbf { j } - 6 \mathbf { k } } { 7 }

D

2i+3j+6k7\frac { 2 \mathbf { i } + 3 \mathbf { j } + 6 \mathbf { k } } { 7 }

Answer

2i+3j6k7\frac { 2 \mathbf { i } + 3 \mathbf { j } - 6 \mathbf { k } } { 7 }

Explanation

Solution

Unit vector perpendicular to both the given vectors is,

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