Question
Question: The unit vector parallel to the resultant of the vectors \(\overset{\rightarrow}{A} = 4\widehat{i} ...
The unit vector parallel to the resultant of the vectors
A→=4i+3j+6kandB→=−i+3j−8k is –
A
(a)71(3i+6j−2k)
A
(b)71(3i+6j+2k)
A
(c)491(3i+6j+2k)
A
(d)491(3i+6j−2k)
Explanation
Solution
(a)
C→=A→+B→ = (3i+6j−2k)
C=∣C∣C→ = 32+62+(–2)23i+6j−2k = 73i+6j−2k