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Question

Physics Question on Electric Current

The unit of thermal conductivity is :

A

J m−1 K−1J\, m^{-1}\,K^{-1}

B

W m−1 K−1W\,m^{-1}\,K^{-1}

C

Wm K−1W m \,K^{-1}

D

J m K−1J\,m\,K^{-1}

Answer

W m−1 K−1W\,m^{-1}\,K^{-1}

Explanation

Solution

The heat current related to difference of temperature across the length ll of a conductor of area AA is dHdt=KAℓΔT\frac{dH}{dt} = \frac{KA}{\ell} \Delta T (K = coefficient of thermal conductivity) ∴K=ℓdHAdtΔT\therefore K = \frac{\ell dH}{Adt \Delta T} Unit of K = Wm−1K−1Wm^{-1}K^{-1}