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Question: The unit of potential energy is...

The unit of potential energy is

A

g(cm/sec⁡2)g(cm/\sec^{2})

B

g(cm/sec⁡)2g(cm/\sec)^{2}

C

g(cm2/sec⁡)g(cm^{2}/\sec)

D

g(cm/sec⁡)g(cm/\sec)

Answer

g(cm/sec⁡)2g(cm/\sec)^{2}

Explanation

Solution

Potential energy =mgh=g(cmsec⁡2)cm=g(cmsec⁡()2)= mgh = g\left( \frac{cm}{\sec^{2}} \right)cm = g\left( \frac{cm}{\sec}()^{2} \right)