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Chemistry Question on Rate of a Chemical Reaction

The unit of ebullioscopic constant is ______.

A

K kg mol−1 K \,kg\, mol^{-1}\, or  K (molality)−1\, K \,(\text{molality})^{-1}

B

mol kg K−1 mol\, kg\, K^{-1}\, or  K−1 (molality)\, K^{-1}\, (\text{molality})

C

kg mol−1 K−1  kg \,mol^{-1} \, K^{-1} \, or  K−1 (molality)−1\, K^{-1}\, (\text{molality})^{-1}

D

K mol kg−1 K \, mol\, kg^{-1} \, or  K (molality)\, K\, \text{(molality)}

Answer

K kg mol−1 K \,kg\, mol^{-1}\, or  K (molality)−1\, K \,(\text{molality})^{-1}

Explanation

Solution

As we know from elevation in boiling point that UU
ΔTb=Kbm\Delta T_b = K_b m

Unit of Kb=Unit of ΔTbUnit of mK_b = \frac{\text{Unit of } \Delta T_b}{\text{Unit of} \,m}
=Kmol kg−1=K mol−1kg= \frac{K}{mol\,kg^{-1}} = K\,mol^{-1} kg