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Chemistry Question on Chemical Kinetics

The unit, mol L−1 s−1mol \, L^{-1} \, s^{-1} is meant for the rate constant of the reaction having the order

A

0

B

2

C

1

D

3

Answer

0

Explanation

Solution

General unit for rate constant = (molL)1−n s−1\big(\frac{mol}{L}\big)^{1-n} \, s^{-1}
(where, n = order of reaction)
Given, unit for rate constant = (molL) s−1\big(\frac{mol}{L}\big) \, s^{-1}
On comparing,
\hspace25mm \big(\frac{mol}{L}\big)^{1-n} \, s^{-1} = \big(\frac{mol}{L}\big) \, s^{-1}
\hspace35mm 1 - n = 1
\therefore \hspace35mm n = 0
Hence, the order of reaction is zero.