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Question

Question: The uncertainty in the position of an electron moving with a velocity of 1.0 × 10<sup>4</sup> cm s<s...

The uncertainty in the position of an electron moving with a velocity of 1.0 × 104 cm s–1 (accurate up to 0.011%) will be –

A

1.92 cm

B

7.68 cm

C

0.528 cm

D

3.8 cm

Answer

0.528 cm

Explanation

Solution

from Dx. Dv = h4πm\frac{h}{4\pi m} Dx =

6.6×10274×(3.14)×(9.1×1028)×(1.0×104×0.011100)\frac{6.6 \times 10^{- 27}}{4 \times (3.14) \times (9.1 \times 10^{- 28}) \times \left( 1.0 \times 10^{4} \times \frac{0.011}{100} \right)}

= 0.528 cm