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Question

Question: The uncertainty in the momentum of an electron is 1.0 × 10–5 kg m s–1 . The uncertainty in its posit...

The uncertainty in the momentum of an electron is 1.0 × 10–5 kg m s–1 . The uncertainty in its position will be:

A

1.05 × 10–28 m

B

1.05 × 10–26 m

C

5.27 × 10–30 m

D

5.25 × 10–28 m

Answer

5.27 × 10–30 m

Explanation

Solution

Δp.Δx=h4π\Delta p.\Delta x = \frac{h}{4\pi}

Δx=6.62×10344×3.14×1×105=5.27×1030m.\Delta x = \frac{6.62 \times 10^{- 34}}{4 \times 3.14 \times 1 \times 10^{- 5}} = 5.27 \times 10^{- 30}m.