Question
Chemistry Question on Structure of atom
The uncertainty in momentum of an electron is 1×10−5kgm/s. The uncertainty in its position will be (Given, h=6.62×10−34kgm2/s)
1.05×10−28m
1.05×10−26m
5.27×10−30m
5.25×10−28m
5.27×10−30m
Solution
The uncertainty in the momentum of an electron is 1 × 10-5 kgm/s
According to the uncertainty principle, it is impossible to precisely identify a particle's position and momentum at the same time. Position and momentum always produce a result that is greater than h/4. The Heisenberg Uncertainty Principle's formula is as:
Δp×Δx≥4πh
Here, h is the Planck’s constant ( 6.62607004 × 10-34 m2 kg / s)
Δp is the uncertainty in momentum
Δx is the uncertainty in position
So, Δp = 1 × 10-5 kgm/s
So, the Uncertainty in position(Δx) will be-
\hspace15mm \Delta p=1\times10^{-5} kg m/s
1×10−5×Δx=4×7226.62×10−34
Δx=10−5×4×226.62×10−34×7
=5.265×10−30m
≈5.27×10−30m
Uncertainty is a basic characteristic of nature.
- We, therefore, came to the conclusion that it is challenging to precisely and concurrently identify a particle's location and momentum.
- Therefore, the concepts of precise location and precise velocity are useless.
- This concept won't be revealed by ordinary scientific experience. It is because it is easy to determine an object's velocity and position.
- This is due to the fact that the implied uncertainty of this concept for typical things is too modest to be seen.
- Because of this, the uncertainty in location and velocity is more than or equal to h, a very, very tiny physical quantity.
- Because of this, this product of uncertainty will only have a very minor impact on atoms and subatomic particles.
Discover more from this chapter:Structure of Atom