Question

The two waves, whose intensities are $9:16$ are made to interfere. The ratio of maximum and minimum intensities in the interference pattern is

• A. 16:09
• B. 4:03
• C. 25:07:00
• D. 49:01:00

Answer 1

Answer: (D)

49:01:00

Answer 2

Amplitude of superimposing waves are
$\left( \frac{{{a}_{1}}}{{{a}_{2}}} \right)={{\left( \frac{9}{16} \right)}^{1/2}}=\frac{3}{4}$
$\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{({{a}_{1}}+{{a}_{2}})}^{2}}}{({{a}_{1}}-{{a}_{2}})}$
$=\frac{{{(3+4)}^{2}}}{{{(3-4)}^{2}}}=\frac{49}{1}$