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Question

Mathematics Question on Equation of a Line in Space

The two vertices of a triangle are (4,2,1)(4,2,1) and (5,1,4)(5,1,4). If the centroid is (5,2,3)(5,2,3), then the third vertex is

A

(3,4,5)(3,4,5)

B

(6,2,3)(6,2,3)

C

(6,3,2)(6,3,2)

D

(6,3,4)(6,3,4)

Answer

(6,3,4)(6,3,4)

Explanation

Solution

Centroid is (xi3,yi3,zi3)\left(\frac{\sum x_{i}}{3}, \frac{\sum y_{i}}{3}, \frac{\sum z_{i}}{3}\right) Let the third vertex be (α,β,γ)\left(\alpha, \beta, \gamma\right). 5=4+5+α3\therefore 5=\frac{4+5+\alpha}{3} α=6\Rightarrow\alpha=6, 2=2+1+β32=\frac{2+1+\beta}{3} β=3,3=1+4+γ3\Rightarrow \beta=3, 3=\frac{1+4+\gamma}{3} γ=4\Rightarrow \gamma=4 \therefore The third vertex is (6,3,4)\left(6 , 3 ,4\right).