Question

The two types of bonds present in ${B_2}{H_6}$ are covalent and ionic bonds. If true enter 1, else enter 0.

Answer 1

In the given question firstly we have to define the exact Diborane are. Now after that we can use this information and do the step by step work of finding the correct option among the following in the case of this problem by process of elimination.

Complete step by step answer:
The given question statement asks about the entire process through which we would be able to get the proper and correct explanation of Diborane. So we have to explain what exactly are the reactions and the correct answer of the problem.
The compound of the Diborane is a chemical compound and has a chemical formula of ${B_2}{H_6}$ . It shows a very unique kind of bonding which is often referred to as the banana bonding and is a widely famous case. It is also called a bent bond which is a type of covalent chemical bond with a geometry somewhat resembling a banana.
The two types of bonds present in ${B_2}{H_6}$ are the covalent bond and three-center two-electron bonds.
Hence the correct option among the following is option 0 and the reason which is mentioned is perhaps false.

Note: Diborane was first synthesised in the 19th century by hydrolysis of metal borides, but it was never analysed. From 1912 to 1936, Alfred Stock, the major pioneer in the chemistry of boron hydrides, undertook his research that led to the methods for the synthesis and handling of the highly reactive, volatile, and often toxic boron hydrides.