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Question: The two monomers for the synthesis of Nylon 6, 6 are: (a)- \(HOOC{{(C{{H}_{2}})}_{6}}COOH,\text{ }...

The two monomers for the synthesis of Nylon 6, 6 are:
(a)- HOOC(CH2)6COOH, H2N(CH2)6NH2HOOC{{(C{{H}_{2}})}_{6}}COOH,\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{6}}N{{H}_{2}}
(b)- HOOC(CH2)6COOH, H2N(CH2)4NH2HOOC{{(C{{H}_{2}})}_{6}}COOH,\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{4}}N{{H}_{2}}
(c)- HOOC(CH2)6COOH, H2N(CH2)4NH2HOOC{{(C{{H}_{2}})}_{6}}COOH,\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{4}}N{{H}_{2}}
(d)- HOOC(CH2)4COOH, H2N(CH2)6NH2HOOC{{(C{{H}_{2}})}_{4}}COOH,\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{6}}N{{H}_{2}}

Explanation

Solution

Nylon 6,6 is a polymer that is formed by condensation polymerization. It is made up of two monomers. The 6,6 in Nylon 6,6 indicates that both the monomers of Nylon 6,6 have 6 carbon atoms each.

Complete step by step answer:
Nylon 6,6 is a polymer. It comes under the polymers which have amide linkage. Amide linkage is formed between the carboxyl group of one molecule and the ammonia group of another molecule. The linkage is −NH−CO−-NH-CO-. The linkage is caused by the elimination of a water molecule.
Nylon 6,6 is a polyamide. It comes under condensation polymerization because there is a loss of water molecules during the polymerization. There are two monomers in Nylon 6,6. These monomers are adipic acid and hexamethylenediamine. The formula of adipic acid is HOOC(CH2)4COOHHOOC{{(C{{H}_{2}})}_{4}}COOH. It is made up of 6 carbon atoms. Each terminal is a carboxylic group. The formula of hexamethylenediamine is  H2N(CH2)6NH2\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{6}}N{{H}_{2}}. It is also a 6 carbon atom molecule. Each terminal carbon atom is attached to the amine group.
The acid and the amine are heated at 525 K under pressure and undergo polymerization with the elimination of water as steam, nylon 6,6 is produced. The reaction of formation of Nylon 6,6 is given below:

Since both the monomers have 6 carbon atoms each, therefore, it is written as Nylon 6,6.
So, the correct answer is - HOOC(CH2)4COOH, H2N(CH2)6NH2HOOC{{(C{{H}_{2}})}_{4}}COOH,\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{6}}N{{H}_{2}}.
So, the correct answer is “Option D”.

Note: There are two more Nylon produced by condensation reaction:
(i)- Nylon 6,10, whose monomers are sebacic acid HOOC(CH2)8COOHHOOC{{(C{{H}_{2}})}_{8}}COOH and hexamethylenediamine  H2N(CH2)6NH2\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{6}}N{{H}_{2}}
(ii)- Nylon 6, whose monomer is 6-Aminohexanoic acid H3N+−(CH2)5−COO−{{H}_{3}}{{N}^{+}}-{{(C{{H}_{2}})}_{5}}-CO{{O}^{-}}.