Question

The two femurs each of cross-sectional area support the upper part of a human body of mass 40 kg. The average pressure sustained by the femurs is (Take

• A. $2 \times 10 ^ { 3 } \mathrm {~N} \mathrm {~m} ^ { - 2 }$
• B.
• C.
• D.

Answer 1

Answer: (C)

Answer 2

Total cross sectional area of the femurs is,

$\mathrm { A } = 2 \times 10 \mathrm {~cm} ^ { 2 } = 2 \times 10 \times 10 ^ { - 4 } \mathrm {~m} ^ { 2 } = 20 \times 10 ^ { - 4 } \mathrm {~m} ^ { 2 }$

Force acting on them is

$\therefore$ Average pressured sustained by them is