Question

The two ends of a train moving with constant acceleration pass a certain point with velocities u and v. The velocity with which the middle point of the train passes the same point is

• A. $(u + v)/2$
• B. $(u^2 + v^2)/2$
• C. $\sqrt{(u^2 + v^2)/2}$
• D. $\sqrt{u^2 + v^2}$

Answer 1

Answer: (C)

$\sqrt{(u^2 + v^2)/2}$

Answer 2

Let the length of train is s, then by third equation of motion, $v^2 = u^2 + 2a \times s$ ....(1) Where v is final velocity after travelling a distance s with an acceleration a & u is initial velocity as per question Let velocity of middle point of train at same point is v', then $(v')^2 = u^2 + 2a \times (s/2)$ ....(2) By equation (1) & (2), we get $v' = \sqrt{\frac{v^2 + u^2}{2}}$