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Question

Physics Question on simple harmonic motion

The two-dimensional motion of a particle, described by r=(i^+2j^)Acosωt\vec{r} = (\hat{i} + 2\hat{j}) A \cos \omega t is a/an:
1. parabolic path
2. elliptical path
3. periodic motion
4. simple harmonic motion
Choose the correct answer from the options given below:

A

B, C and D only

B

A, B and C only

C

A, C and D only

D

C and D only

Answer

C and D only

Explanation

Solution

Let the position vector be r=xi^+yj^\vec{r} = x\hat{i} + y\hat{j}. Then:

x = A cos ω t

y = 2 A cos ω t

This represents simple harmonic motion along both the x and y axes.

xA\frac{x}{A} = cos ωt

y2A\frac{y}{2A} = cos ωt

Therefore: xA=y2A\frac{x}{A} = \frac{y}{2A}

y = 2 x

This is the equation of a straight line, so the path is not parabolic or elliptical.

The motion is periodic and simple harmonic along the line y = 2x.