Question

The $TV$ signals have a bandwidth of $3.7\, MHz$. The number of $TV$ channels that can be accommodated with a band of $3700 \,GHz$ is

• A. $10^4$
• B. $10^5$
• C. $10^6$
• D. $10^7$

Answer 1

Answer: (C)

$10^6$

Answer 2

Here,
Bandwidth of each channel= $3.7 MHz$
$= 3.7 \times 10^6 \, Hz$
Total bandwidth $= 3700 \, GHz= 3700 \times 10^9 \, Hz$
Number of TV channels accomodated
$= \frac{Total \, bandwidth}{Bandwidth\, per\, channel}= \frac{3700 \times 10^9}{3.7 \times 10^6} = 10^6$