Question

The truth table shown in figure is for

A 0 0 1 1

B 0 1 0 1

Y 1 0 0 1

• A. XOR
• B. AND
• C. XNOR
• D. OR

Answer 1

Answer: (C)

XNOR

Answer 2

For ‘XNOR’ gate $Y = \bar{A}\bar{B} + AB$

i.e. $\bar{0}.\bar{0} + 0.0 = 1.1 + 0.0 = 1 + 0 = 1$

$\bar{0}.\bar{1} + 0.1 = 1.0 + 0.1 = 0 + 0 = 0$

$\bar{1}.\bar{0} + 1.0 = 0.1 + 1.0 = 0 + 0 = 0$

$\bar{1}.\bar{1} + 1.1 = 0.0 + 1.1 = 0 + 1 = 1$