Question

The truth table for the following logic circuit is.

• A. $\left| \begin{array} { l l l } A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \end{array} \right|$
• B. $\left| \begin{array} { l l l } A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \end{array} \right|$
• C.
• D. $\left| \begin{array} { c c c } A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \end{array} \right|$

Answer 1

Answer: (A)

$\left| \begin{array} { l l l } A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \end{array} \right|$

Answer 2

:

The truth table for the given logic circuit is

A				B			$\bar{A}$		$\bar{B}$		$\bar{A}.B$	$A.\bar{B}$	$Y = \bar{A}.B + A.\bar{B}$
0				0			1		1		0	0	0
0				1			1		0		1	0	1
1				0			0		1		0	1	1
1				1			0		0		0	0	0