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Question: The triangle PQR is inscribed in the circle \(x ^ { 2 } + y ^ { 2 } = 25\). If Q and R have co-ordin...

The triangle PQR is inscribed in the circle x2+y2=25x ^ { 2 } + y ^ { 2 } = 25. If Q and R have co-ordinates (3,4) and (– 4, 3) respectively, then QPR\angle Q P R is equal to.

A

π2\frac { \pi } { 2 }

B

π3\frac { \pi } { 3 }

C

π4\frac { \pi } { 4 }

D

π6\frac { \pi } { 6 }

Answer

π4\frac { \pi } { 4 }

Explanation

Solution

Here the centre . So ‘m’ of OQ is 43\frac { 4 } { 3 }and ‘m’ of OR is 34\frac { - 3 } { 4 }, ∴ QOR=π2\angle Q O R = \frac { \pi } { 2 }

Hence QPR=12×π2=π4\angle Q P R = \frac { 1 } { 2 } \times \frac { \pi } { 2 } = \frac { \pi } { 4 } .