The translatory kinetic energy of a gas per gm is – | PHYSICS - KINETIC THEORY OF AN IDEAL GAS | SolveeIt | Solveeit

Today, August 19

Question

The translatory kinetic energy of a gas per gm is –

A

$\frac{3}{2}\frac{RT}{N}$

B

$\frac{3}{2}\frac{RT}{M}$

C

$\frac{3}{2}RT$

D

$\frac{3}{2}NKT$

Answer

$\frac{3}{2}\frac{RT}{M}$

Explanation

Solution

Kinetic energy for 1gm Ž E_Trans. = $\frac{3}{2}$ rT = $\frac{3}{2}\frac{RT}{M}$