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Question

Question: The translational kinetic energy of gas molecule for one mole of the gas is equal to...

The translational kinetic energy of gas molecule for one mole of the gas is equal to

A

32RT\frac{3}{2}RT

B

23RT\frac{2}{3}RT

C

12RT\frac{1}{2}RT

D

23KT\frac{2}{3}KT

Answer

32RT\frac{3}{2}RT

Explanation

Solution

Kinetic energy for 1 mole gas E=f2RTE = \frac{f}{2}RT

Ž ETranslation=32RTE_{\text{Translation}} = \frac{3}{2}RT

(\becauseFor all gases translational degree of freedom f = 3)