Question

The transfer ratio of a transistor is 50. The input resistance of the transistor when used in the common-emitter configuration is 1 KΩ. The peak value for an ac input voltage of 0.01 V peak is

• A. 100 μA
• B. 0.01 Ma
• C. 0.25 mA
• D. 500 μ A

Answer 1

Answer: (D)

500 μ A

Answer 2

$i_{c} = \beta i_{b} = \beta \times \frac{V_{i}}{R_{i}} = 50 \times \frac{0.01}{1000} = 500 \times 10^{- 6}A = 500\mu A$