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Question: The transfer ratio of a transistor is 50. The input resistance of the transistor when used in the co...

The transfer ratio of a transistor is 50. The input resistance of the transistor when used in the common-emitter configuration is 1 KΩ. The peak value for an ac input voltage of 0.01 V peak is

A

100 μA

B

0.01 Ma

C

0.25 mA

D

500 μ A

Answer

500 μ A

Explanation

Solution

ic=βib=β×ViRi=50×0.011000=500×106A=500μAi_{c} = \beta i_{b} = \beta \times \frac{V_{i}}{R_{i}} = 50 \times \frac{0.01}{1000} = 500 \times 10^{- 6}A = 500\mu A