Question

The transfer ratio $\beta$ of a transistor is $50$. The input resistance of the transistor when used in the common-emitter configuration is $1 k\Omega$ The peak value of the collector A.C. current for an A.C. input voltage of 0.01 V peak is

• A. $0.25\, \mu A$
• B. $0.01 \, \mu A$
• C. $100\, \mu A$
• D. $500\, \mu A$

Answer 1

Answer: (D)

$500\, \mu A$

Answer 2

Given, $\beta=50\, V=0.01 \,V$ and $R=1 \,k \Omega=1000 \,\Omega$ Here, $\beta=\frac{i_{c}}{i_{b}}$ $\frac{i_{c}}{i_{b}} =50$ $\left(i_{b}\right)_{\max } =\frac{0.01}{1000}=1 \times 10^{-5} \,A$ $\left(i_{c}\right)_{\max } =\left(i_{b}\right)_{\max } \times \beta$ $\left(i_{c}\right)_{\max } =\left(1 \times 10^{-5}\right) \times 50$ $\left(i_{c}\right)_{\max }=500\, \mu A$