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Question

Physics Question on projectile motion

The trajectory of a projectile projected from origin is given by the equation y = x - 2x25\frac{2x^2}{5} . The initial velocity of the projectile is

A

25ms125\, ms^{-1}

B

25ms1\frac{2}{5} ms^{-1}

C

52ms1\frac{5}{2} ms^{-1}

D

5ms15 ms^{-1}

Answer

5ms15 ms^{-1}

Explanation

Solution

y=x2x25y=x -\frac{2x^{2}}{5} tanθ=1tan \, \theta=1 θ=45\theta=45^{\circ} g2u2cos2θ=25\frac{g}{2u ^{2} cos ^{2}\theta}=\frac{2}{5} 102u212=25\frac{10}{2u^{2} \frac{1}{2}}=\frac{2}{5} u2=502=25u^{2}=\frac{50}{2}=25 u=5ms1u=5 \, ms^{-1}